mols dichromate = 2/257.07 = ?
?mols dichromate x 5 mols gas products x 22.4 L/mol x (298/273) = ? L - change in volume. Then w = -pdV = -1 atm x ?L = ? L/atm and that x 101.325 J/L-atm = -0.946
A popular volcano demonstration involves the thermal decomposition of ammonium dichromate: (NH4)2Cr2O7 (s) --> Cr2O3 (s) + N2 (g) + 4 H2O (g)
How much work is done by the system when 2.00 g of ammonium dichromate (M: 257.07 g/mol) completely decomposes? Assume that the final temperature is 298 K.
The answer is suppose to be +/-96.4 J.
I tried this question and got 19.3 J using w= -deltan RT.
Please tell me how to get the right answer.
2 answers
Just wondering where you got 22.4 L/mol
0 answers