A popular entertainment at some carnivals is the blanket toss.

Question

(a) If a person is thrown to a maximum height of 26.0 ft above the blanket, how long does she spend in the air?
(b) Is the amount of time the person is below a height of 13.0 ft more than, less than, or equal to the amount of time the person is above a height of 13.0 ft?
Explain
(c) Verify your answer to part (b) with some calculations.
_______ s (time below 13.0 ft)
_______ s (time above 13.0 ft)

Answer 1

(a) Twice the fall time (t) from a height of h = 26 ft.
The fall time t is given by
(g/2)t^2 = h
So,
t = sqrt(2h/g)= 1.27 s
Use g = 32.2 ft/s^2

2t = 2.54 s

(b) Average speed is lower at the top half. That makes the time spent there longer than is is on the bottom half.

(c) Calculate the time it takes to fall 13.0 ft starting at velocity 0 . I get 0.899 s
1.27 s minus that time is the time spent in the lower half

Answer 2

a. t=sqrt(2h/g)=1.27s(2)= 2.54 s
b. the amount of time the person is above the height of 13.0 ft is more than the amount of time that person is below the height of 13.0 ft
c. x=vt+1/2at^2=0.933 s
1.27 s-0.933 s=0.371 s in the lower half

Answer 3

can you show how part C is calculate?

Answer 4

Don't forget to multiply your answer for C by 2, to get the total time!

Answer 5

^^^ you're a life saver