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Original Question
A polyhedron with 12 faces and 18 edges would have how many vertices?Question
A polyhedron with two faces, and 18 edges would have how many vertices
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GPT 3.5
The formula for calculating the number of vertices in a polyhedron is given by Euler's formula:
V - E + F = 2,
where V is the number of vertices, E is the number of edges, and F is the number of faces.
Given that the polyhedron has 2 faces and 18 edges, we can substitute these values into Euler's formula:
V - 18 + 2 = 2.
Solving for V, we get:
V = 18 + 2 - 2 = 18 vertices.
Therefore, the polyhedron with two faces and 18 edges would have 18 vertices.
V - E + F = 2,
where V is the number of vertices, E is the number of edges, and F is the number of faces.
Given that the polyhedron has 2 faces and 18 edges, we can substitute these values into Euler's formula:
V - 18 + 2 = 2.
Solving for V, we get:
V = 18 + 2 - 2 = 18 vertices.
Therefore, the polyhedron with two faces and 18 edges would have 18 vertices.
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