A polyhedron with 8 faces and 14 vertices would have 20 edges.
This can be determined using Euler's formula for polyhedra:
(Number of faces) + (Number of vertices) - (Number of edges) = 2.
Plugging in the values, we get:
8 + 14 - x = 2
22 - x = 2
x = 20
Therefore, the polyhedron would have 20 edges.
a polyhedron with 8 faces and 14 vertices would have how many edges?
1 answer