a political discussion group consists of five Democrats and six Republicans. Four people are selected to attend a conference.
A.in how many ways can four people be selected from this group of eleven?
B.In how many ways can four Republicans be selected from six Republicans?
C.find the probability that the selected group will consist of all Republicans?
9 answers
the answer is "C"
Thanks, but i need the answer to all three questions
A) choose 4 from 11 which is C(11,4) or 330
b) choose 4 from 6 which is C(6,4) or 15
c) assuming that your group still consists of 4 people
prob = 15/330 = 1/22
b) choose 4 from 6 which is C(6,4) or 15
c) assuming that your group still consists of 4 people
prob = 15/330 = 1/22
thank you
A. 11 x 10 x 9 x 8/(4 x 3 x 2 x 1) = 330
B. 6!/(4!*2!) = 15
C. (6/11)*(5/10)*(4/9)*(3/8) = 0.04545
B. 6!/(4!*2!) = 15
C. (6/11)*(5/10)*(4/9)*(3/8) = 0.04545
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A political discussion group consists of 6 Democrats and 10 Republicans. Five members are selected to attend a conference. Find the probability that the group will consist of all Democrats.
1 answer