A police car is traveling at a velocity of 20.0 m/s due north, when a car zooms by at a constant velocity of 44.0 m/s due north. After a reaction time 0.700 s the policeman begins to pursue the speeder with an acceleration of 6.00 m/s^2. Including the reaction time, how long does it take for the police car to catch up with the speeder?
44(t+0.7) = 20t + 3t^2
3t^2 - 24t - 30.8 = 0
I plugged this into the quadratic formula but I cannot seem to get the correct answer. Please help.