a. find the speed from the height he fell.
b. force*time=mass(changeinVelocityatImpact)
A pole-vaulter of mass 59.9 kg vaults to a height of 5.9 m before dropping to thick padding placed below to cushion her fall.
(a) Find the speed with which she lands.
m/s
(b) If the padding brings her to a stop in a time of 0.48 s, what is the average force on her body due to the padding during that time interval?
N
I have no clue how to even start this! If someone could help, then please; I would appreciate it!
4 answers
Do I use kinematic equation for part a?
And what would be the force for part b?
Thank you!
And what would be the force for part b?
Thank you!
From the law of conservation of energy:
PE = KE
mgh = mv^2/2
v=sqr(2gh)=sqr(2•9.8•5.9)=10.75 m/s
F=ma=m•Δv/Δt=59.9•10.75/0.48=1342 N
PE = KE
mgh = mv^2/2
v=sqr(2gh)=sqr(2•9.8•5.9)=10.75 m/s
F=ma=m•Δv/Δt=59.9•10.75/0.48=1342 N
Thank you Elena :) !
1 answer