PEi + KEi = PEf + KEf
mgh + (0) = (0) + (1/2)mv^2
mgh = (1/2)mv^2
(9.8)(4.07)m = 3900
m = 97.8 kg
Fg = mg = (9.8)(97.8)
Fg = 958 N
A pole-vaulter just clears the bar at 4.07 m and falls back to the ground. The change in the vaulter's potential energy during the fall is -3900 J. What is his weight?
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