A pole AB of length 10m and weight 600N has its centre of gravity 4m from the end A, and lies on horizontal fround.calculate the force required to begin to lift the end.why would this force applied at the end A,not be sufficient to lift the end A?

Answer 1

F * 10 = 600 * 4
F = 600 * .4 = 240 N

if you tried to lift at the other end
F2* 10 = 600 * 6
F2 = 360 N

Answer 2

Clock wise moment=600×4=2400NM Anticlockwise moment=p×10=p10NM Equilibrium:2400=10pNM divide both sides by 10 Therefore p=240