The distance of the aperture from the light source only determines the intesnth, not the size of the bright "patch" of light on the other side.
It is customary to assume an average wavelength of visible light of 550 nm when no other wavelength infrmation is given.
What you can conclude from the information you have been given is the diameter of the aperture. You did not ask that question, however.
I believe the correct formula to use for the angular with of the light patch is
"Airey diffrection pattern" formula
theta = 1.22*(Lambda)/D
where lambda = 550*10^-9 m is
the wavelength
In your case, theta = 0.18/2 = 0.09 radians, so
D = 1.22*550*10^-9/0.09 = 7.6*10^-6 m
= 7.6*10^-3 mm
a quite small hole.
A point source of light illuminates an aperture 4.00m away. A 18.0 cm -wide bright patch of light appears on a screen 2.00m behind the aperture.
I have been trying to use the equation w=(2*wavelength*distance)/aperature width. However, I am not given wavelength and the type of light is not specified. Also, does the source of light being 4.00m away from the aperature even matter?
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1 answer