A point is rotated about the origin. Its coordinates are  P(−4,10) and P′(−10,−4) . Determine the degree of rotation and direction by applying rotation mapping.(1 point) Responses −180 degrees (clockwise) or 180 degrees (counterclockwise) negative 180 degrees (clockwise) or 180 degrees (counterclockwise) 270 degrees (counterclockwise) 270 degrees (counterclockwise) −90 degrees (clockwise) negative 90 degrees (clockwise) 90 degrees (counterclockwise)

1 answer

To determine the angle of rotation that takes point \( P(-4, 10) \) to point \( P'(-10, -4) \), we can analyze their positions in relation to the origin.

  1. Identify the original and new coordinates:

    • \( P(x_1, y_1) = (-4, 10) \)
    • \( P'(x_2, y_2) = (-10, -4) \)
  2. Determine the direction and angle of rotation: To find the angle of rotation, we will use the formula for rotation of a point around the origin. The general rotation transformation is given by:

\[ \begin{pmatrix} x' \ y' \end{pmatrix}

\begin{pmatrix} \cos \theta & -\sin \theta \ \sin \theta & \cos \theta \end{pmatrix} \begin{pmatrix} x \ y \end{pmatrix} \]

We will check the coordinates:

After rotation by \( \theta \):

  • For point \( P(-4, 10) \):

\[ x' = -4 \cos \theta + 10 \sin \theta \] \[ y' = -4 \sin \theta + 10 \cos \theta \]

This should equal \( P'(-10, -4) \): \[ -4 \cos \theta + 10 \sin \theta = -10 \quad (1) \] \[ -4 \sin \theta + 10 \cos \theta = -4 \quad (2) \]

  1. Substituting values and calculating the angle \(\theta\):

Let's analyze the coordinates geometrically:

  • The original point \( P(-4, 10) \) is in the second quadrant.
  • The new point \( P'(-10, -4) \) is in the third quadrant.

Finding the angle of rotation:

We can calculate the angle from the origin to both points.

For point P:

\[ \tan^{-1}\left(\frac{y}{x}\right) = \tan^{-1}\left(\frac{10}{-4}\right) = \tan^{-1}\left(-\frac{5}{2}\right) \approx 180 - \theta \quad (\text{since it's in the second quadrant}) \]

So, the angle for \( P \) is approximately \( 180 - \theta \).

For point P':

\[ \tan^{-1}\left(\frac{-4}{-10}\right) = \tan^{-1}\left(\frac{2}{5}\right) \text{ (since both coordinates are negative, it's in the third quadrant)}. \]

Thus, the angle corresponding to \( P' \) is \( 180 + \tan^{-1}\left(\frac{2}{5}\right)\).

Calculating rotation angle:

The angle moved from \( P \) to \( P' \) can be computed.

We find:

  1. From initial approximate angle values, \( P \approx 180^\circ - \theta \)
  2. \( P' \approx 180^\circ + \tan^{-1}\left(\frac{2}{5}\right) + 180^\circ \)

Verifying angle shift:

Calculating the shift gives you \( 180^\circ \).

Final Result:

The rotation from \( P \) to \( P' \) can be confirmed as \( 180^\circ \) counterclockwise or \( -180^\circ \) clockwise.

Conclusion:

Thus, the answer is:

180 degrees (counterclockwise) or −180 degrees (clockwise).