LOL trick question
It does not matter what the shape is.
The total flux depends only on how much charge is inside. (Google Gauss Law)
4 pi * the charge inside
A Point charge of 10.5uC is located inside a cube, what is the net electric flux?
3 answers
Come again? I'm a little bit slow in terms of understanding, it means it cannot be solve without its shape or length? Etc how about 3.5uC?
I can not give you a link but try searching with
wikipedia.org/wiki/Gauss's_law
The total flux out does not depend on the size or shape of the surface, only on how much charge is inside. As your distance from the charge goes up, E goes down at the same rate (1/r^2) as surface area goes up so the flux is the same. What comes out depends only on what is inside, not the size or shape of the container. It is as if you had a hose in there pouring out a gallon a minute. No matter what your containment shape, a gallon a minute comes through.
wikipedia.org/wiki/Gauss's_law
The total flux out does not depend on the size or shape of the surface, only on how much charge is inside. As your distance from the charge goes up, E goes down at the same rate (1/r^2) as surface area goes up so the flux is the same. What comes out depends only on what is inside, not the size or shape of the container. It is as if you had a hose in there pouring out a gallon a minute. No matter what your containment shape, a gallon a minute comes through.