Assuming a) is right.
b) how long does it take to get to the wall plane? time= 24/(19.9cosTheta)
Now using that time..
vertical height= 19.9sinTheta*t-1/2 g t^2
and clearance is that minus 8m
A playground is on the flat roof of a city school, 7.00 m above the street below. The vertical wall of the building is 8.00 m high, forming a 1.00 m high railing around the playground. A ball has fallen to the street below, and a passerby returns it by launching it at an angle of 53.0° above the horizontal at a point 24.0 m from the base of the building wall. The ball takes 2.00 s to reach a point vertically above the wall.
I had solved for A, but I am unable to solve for B and C, it says that I was off by 10-100%.
(a) Find the speed at which the ball was launched. 19.9 m/s
(b) Find the vertical distance by which the ball clears the wall.
(c) Find the distance from the wall to the point on the roof where the ball lands.
1 answer
2 answers