A player kicks a footbal with a velocity of 27 m/s at an angle of 31° with the ground. How high does the ball travel?

Answer 1

Vo = 27m/s @ 31deg.

Vo(ver) = 27sin31 = 13.91m/s.

Vf = Vo + gt = 0 @ max. height.
13.91 - 9.8t = 0,
9.8t = 13.91,
t = t = 1.42s = time to reach max. ht.

hmax=13.91*1.42 + 0.5*(-9.8*(1.42)^2,
hmax = 19.75 - 9.85 = 9.9m.