A play has two roles for men and four roles for women if five men and 12 women tryout for these parts,in how many different ways can the director choose people for the roles
4 answers
5P2 * 12P4 = ?
Ever tried wolfram alpha? The answer to your equation here though I've figured is 480. 48 possible arrangements of women to their roles and 10 to the men, in such a situation. to find the possible arrangement for the two combined we must then multiply as each combination counts. 48 times 1 = 48 add the 0 = 480.
The men positions can be filled in (5)(4) or 20 ways.
The women position can be filled in (12)(11)(10)(9) or 11880 ways
Which is exactly what Steve had in
P(5,2) * P(12,4) = 20(11880) = 237600 ways
So go with Steve's answer.
The women position can be filled in (12)(11)(10)(9) or 11880 ways
Which is exactly what Steve had in
P(5,2) * P(12,4) = 20(11880) = 237600 ways
So go with Steve's answer.
can someone help me with this problem:There was a country concert held at the park. For every 5 men there were 3 women that went to the concert. If 72 total people attended the concert, how many men and how many women each attended the concert? Because i searched it and it gives me the wrong anwser.
2 answers