a plane with an airspeed of 192mi/h is headed on a bearing of 121 degrees. a north wind is blowing (from north to south) at 15.9 mi/h . find the ground speed and the actual bearing of plane.

Answer 1

I will assume you are using the standard 'true north' reference and a clockwise rotation resulting a vector in the fourth quadrant with a magnitude of 192.

draw a vector from the end of the previous vector due south with a magnitude of 15.9

draw in the resultant vector

by cosine law:
R^2 = 192^2 + 15.9^2 - 2(192)(15.9)cos 121º

R will be the ground speed.

Use the Sine Law to find the angle across from the 15.9 side, add that angle to 121 and you have your actual bearing.

Answer 2

is it gonna be right traingle or what?

Answer 3

*
* *
15.9 * 121 *
* *
*))90 (( *
**************
192

Answer 4

10.76