A plane travels 1000 km at an angle of 40 degrees East to North, then changes direction and travels 500 km at an angle of 20 degrees North to East. What is the magnitude and direction of the planes total displacement?

Answer 1

I guess you mean north of east and east of north

east = 1000 cos 40 + 500 sin 20

north = 1000 sin 40 + 500 cos 20

east = 937
north = 1113

distance = sqrt(937^2+1113^2)

tan angle north of east = 1113/937