A plane points its nose due north and flies at a speed of 71 m/s relative to the air. The plane enters a strong wind that blows at a speed of 23 m/s due west relative to the ground. What is the angle of the plane's trajectory according to an observer standing on the ground? Assume that we measure the angle in degrees with respect to due east, so 0° would be due east, 90° would be due north, etc.

asked by Carissa

10 years ago

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1 answer

Vp = Vo + Vw = 71i - 23 = -23 + 71i.

Tan Ar = 71/-23 = -3.08696
Ar = -72.0o S. of E.
A = -72.0 + 180 = 108o CCW.

answered by Henry

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Question

A plane points its nose due north and flies at a speed of 71 m/s relative to the air. The plane enters a strong wind that blows at a speed of 23 m/s due west relative to the ground. What is the angle of the plane's trajectory according to an observer standing on the ground? Assume that we measure the angle in degrees with respect to due east, so 0° would be due east, 90° would be due north, etc.

1 answer

Vp = Vo + Vw = 71i - 23 = -23 + 71i.

Tan Ar = 71/-23 = -3.08696
Ar = -72.0o S. of E.
A = -72.0 + 180 = 108o CCW.

Ask a New Question or answer this question.

Henry · Answer

Vp = Vo + Vw = 71i - 23 = -23 + 71i. Tan Ar = 71/-23 = -3.08696 Ar = -72.0o S. of E. A = -72.0 + 180 = 108o CCW.