A plane leaves an airport x,20-60E and 36-80N and flies due south along the same longitude for 8hours at the rate of 1000km/h to another airport Y,20-60E and titaS.the plane then flies west to another airport Z for 8hours at the same speed. Calculate to the nearest degree (a) the value of tita. (b) the longitude of Z

Answer 1

wow - can you make heads or tails of that gibberish? I assume that 22-60 means 22°60'. No idea what "tita" means. Must be "theta".

At any rate, since the circumference of the earth is about 40,000 km, the plane flew 8000km = 1/5 of the way around the earth. That is 360/5 = 72°. Starting from 36°80'N, that puts him at Y=35°20'S.

The length of a line of latitude at an angle x is 40000 cos(x) km. That means that the "circumference" of the earth at 35°20'S is 40000*0.8158 = 32632km.

At that latitude, 8000km is 0.245*360° = 88°15' westward. Starting from 20°60'E, he ends up at longitude 67°15'W.

Hmmm. I just noticed that 22-60E cannot be 22°60', since 60' = 1° so no one would write that. So, fix my misinterpretation and follow the steps to the correct result.