A plane leaves an airport and flies at 36 mph on a course of 103.25° for 1 hour and 33 minutes. Then it changes course to 236.75° and flies for 48 minutes. How far is it from the airport? If it wished to return, what would be its course?

Answer 1

Draw a diagram. Use the law of cosines, since you have two sides and the angle between them, and want to find the 3rd side.

To get you started, the angle between the two sides is 33.25+13.25=47.5°
actually, that's (270-236.25)+(103.25-90).

To get the side lengths, remember that distance=speed*time