A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.
a. Find BC, the distance from Tower 2 to the plane, to the nearest foot.
b. Find CD, the height of the plane from the ground, to the nearest foot.
Please show work! It is not multiple choice. Im desperate.
5 answers
search this question for the diagram.
All you need to do is tell us the angle at tower A and the angle at tower B, and then you can use the sum of the angles in a triangle add up to 180 degrees to get the angle at C (the plane) then the SINE LAW will help you to figure out the rest :)
Have you thought about dropping a height to your triangle and thus making right angled triangles and going that route (since your diagram might not give you the angles at A and B)
I think more information is needed. Just given the angles of elevation, and the side AB, you can see that the distance from CD to AB gives different solutions for the height CD. Some other angle or distance is needed to pin it all down.
this website has gone all the way downhill since the bot invasion
1 answer