A plane is located at C on the diagram. There are two towers located at A and B. The distance between the towers is 7,600 feet, and the angles of elevation are given.
a. Find BC, the distance from Tower 2 to the plane, to the nearest foot.
b. Find CD, the height of the plane from the ground, to the nearest foot.
It is a right triangle.
The answer should = 6,122. I just need to know how.
If you look this question on openstudy, you can find the triangle I am talking about, it has a base of 7,600 and a couple degrees of 16 and 24. I solved #a, but I am still stuck on #b. Somebody said "sin24 = cd/bc", but I don't know how to solve it. BC = 15,052, that's all I have.
So I guess it would look like this to begin with?:
sin24 = CD/15,052
Step by step would be the best:)
6 answers
How did you find a part of the assessment?
Ms Sue will you help me with this please. I have the answer but not the steps.
B=180-24=156
ACB=180-156-16=8
sinA/a=sinC/c, sin16/a=sin8/7600
solve for a
BC=15052 ft
sin(B)=CD/d, sin(24)=x/15052
15052 sin(24)=x
solve for x
CD=1622 ft
ACB=180-156-16=8
sinA/a=sinC/c, sin16/a=sin8/7600
solve for a
BC=15052 ft
sin(B)=CD/d, sin(24)=x/15052
15052 sin(24)=x
solve for x
CD=1622 ft
I don't get it can you explain how you got that answer
@idc I’m confused can you go into more detail
i miss mrs sue
1 answer