The time to reach the ground from an altitude of 5670 meters derives from h = Vo(t) + g(t^2)/2 where Vo = 73m/s.
Therefore, 5670 = 73t + 4.9t^2 from which t = 27.373 sec.
The horizontal distance traveled is d = 27.373(244) = 6679m.
A plane is flying horizontally with speed 244 m/s at a height 5670 m above the ground, when a package is thrown downward from the plane with a vertical speed v(initial) = 73 m/s.
What horizontal distance is traveled by this package?
The acceleration of gravity is 9.8 m/s2 .
Neglecting air resistance, when the package hits the ground
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