a plane initially at rest accelerates down a runway reaching a velocity of 270km/h [e] in 27.0s what is the acceleration of the plane during take-off

Answer 1

To find the acceleration of the plane during take-off, we can use the formula:

acceleration = (final velocity - initial velocity) / time

First, we need to convert the final velocity from km/h to m/s:

270 km/h = 270,000 m / 3600 s = 75 m/s

Next, because the plane was initially at rest, the initial velocity is 0 m/s.

Now we can plug the values into the formula:

acceleration = (75 m/s - 0) / 27.0 s
acceleration = 75 m/s / 27.0 s
acceleration = 2.78 m/s^2

Therefore, the acceleration of the plane during take-off is 2.78 m/s^2.