I assume you are studying vectors.
Draw a line at 28° of length 200 (your resultant)
Draw a line at 38° of length 207, join its tail to the first line.
That smaller line will be the vector representing the wind
I see a triangle with sides 200 and 207, with a contained angle of 10°
Let the length of the smaller side be x
by cosine law:
x^2 = 200^2 + 207^2 - 2(200)(207)cos10°
etc.
x will be you speed of the wind, and from your diagram it should be straightforward to find the wind direction
A plane has an airspeed of 200 miles per hour and a heading of 28.0°. The ground speed of the plane is 207 miles per hour, and its true course is in the direction of 38.0°. Find the speed and direction of the air currents, assuming they are constants. (Round your answers to one decimal place.)
_____mi/hr at ____° from due north
2 answers
I got calculated 36.1 to one decimal point. And the wind direction I believe should be 200. Do not trust my answer. Thanks!