A plane flies northward for 430km.it then flies eastwards for 380km .How far does it go from the starting point.(answer with a sketch of a right-angled triangle which contains the unknown)

Answer 1

To find the distance from the starting point, we can use the Pythagorean theorem.

Let the northward distance be the vertical leg of the triangle (430 km) and the eastward distance be the horizontal leg of the triangle (380 km). The hypotenuse, which represents the distance from the starting point, can be found by using the Pythagorean theorem:

a^2 + b^2 = c^2
(430)^2 + (380)^2 = c^2
184900 + 144400 = c^2
329300 = c^2
c ≈ √329300
c ≈ 573.57 km

Therefore, the distance from the starting point is approximately 573.57 km.

[Your sketch of a right-angled triangle with legs 430 km and 380 km and hypotenuse labeled as c ≈ 573.57 km]