A plane flew 150 miles on a course of 220 degrees and then 130 miles on a course of 130 degrees. Then the plane returned to it's starting point via the shortest route possible. Find that shortest distance.

Answer 1

The individual displacements are
150 @ 220° = (-96.4,-114.9)
130 @ 130° = (99.6,-83.6)

So, the final location is at (3.2,-198.5)

Just find the distance from there to the origin.