A pitcher throws a baseball straight into the air with a velocity of 72 feet/sec. If acceleration due to gravity is -32 ft/sec2, how many seconds after it leaves the pitcher's hand will it take the ball to reach its highest point? Assume the position at time t = 0 is 0 feet.

Answer 1

height = -16t^2 + 72t + 0

so you want the vertex of this parabola
t of the vertex = -72/-32
= 2.25 seconds to reach the max

height = -16(2.25)^2 + 72(2.25) = 81