A pitched ball is hit by a batter at a 40° angle and just clears the outfield fence, 106 m away. If the fence is at the same height as the pitch, find the velocity of the ball when it left the bat. (Ignore air resistance)

Answer 1

well, plugging your numbers into the equation of motion,

y = .839x - 8.35x^2/v^2

so, plug in y(106) = 0
since the pitch and the fence are the same height.

That will give v.