A pistol of mass 2kg fires a bullet of mass 50g. The bullet strikes a block of mass 0.5kg. If the block with bullet embedded in it moves with a velocity of 4m/s the recoil velocity of the gun will be..??

9 answers

find bullet momentum from conservation of momentum
.05 v = .55 * 4 = 2.2

then
2 V + 2.2 = 0
V = -2.2/2
correct -1.10
@damon can you please explain it...
0.5 and 0.55 are not given in the Q.
just memorizing don't work in physics when u cant explain the answer
mass of bullet and block = 1.1/2
momentum = 1.1/2¡Á4 = 2.2kg.m/s
2.2= 2¡Á velocity of bullet
velocity=-1.10m/s
-1.110 m/s
plzzz explain ...... i m not geeting
plzzz explain ...... i m not geeting
what is the ans