A pipe has a cross sectional radius of 6.00 cm and is carrying water moving at .380 m/sec. If the pipe narrows to a radius of 3.50 cm, what will be the speed of the water in the narrow segment? What is the flow rate in each segment?

Question

thank you!!!!!!!

Answer 1

lAW OF CONTINUITY:

area1*speed1=area2*speed2
speednarrow=PI(6^2)*.380/(.350^2)

volume flow rate=speed*area do that for both sides.

Answer 2

oops, add a PI in the denominator of the law of continuity, area=pI*radius^2