A piece of wire of length 240 cm is bent into the shape of trapezium where the eqtn is = 13x+13x+y+y+24x. Find the value of x and y for which A is maximum, hence find the maximum area.
a. express y in term of x
b. show that the area A cm^2 enclosed by the wire is given by 2880x-540x^2.
[ans: y= (240-50x)/2 , y=160/3, x= 8/3 , max area=3840.]
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can any1 plz answer this question.
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