A piece of wire is 67.95cm long. It is bent to form the sides of a triangle in the ration 2:3:4. Find the length of the longest side of the triangle.

Answer 1

Let the sides of the triangle be 2x, 3x, and 4x.

Then, we know that the total length of the wire is the sum of the lengths of these sides:

2x + 3x + 4x = 9x

We also know that the total length of the wire is 67.95cm:

9x = 67.95cm

Dividing both sides by 9, we get:

x = 7.55cm

Therefore, the longest side of the triangle is 4x, which is:

4(7.55cm) = 30.2cm

So the length of the longest side of the triangle is 30.2cm.