Asked by Anonymous
A piece of wire 18 m long is cut into two pieces. One piece is bent into a square and the other is bent into a circle.
(a) How much wire should be used for the square in order to maximize the total area?
(a) How much wire should be used for the square in order to maximize the total area?
Answers
Answered by
Steve
If x is allocated to the square, that leaves 18-x for the circle. So,
r = (18-x)/2π
a = π((18-x)/2π)^2 + (x/4)^2
= (1/4π + 1/16)x^2 - 9/π x + 81/π
now just set da/dx=0 and solve for x
r = (18-x)/2π
a = π((18-x)/2π)^2 + (x/4)^2
= (1/4π + 1/16)x^2 - 9/π x + 81/π
now just set da/dx=0 and solve for x
Answered by
franciscocbsas
BACON!!!!
Answered by
Anonymous
true
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