a piece of silver metal is taken from a furnace where the temperature is 75C and placed on large block of ice T 0.0C. assuming that all heat is given up by the silver is used to melt the ice,how much ice is melted?

2 answers

Csilver * mass of silver * 75 = mass of ice * heat of fusion of water
Summation of Q = 0
Qsilver + Qice = 0

Qsilver = (mass of silver)(Csilver)(final temp - initial temp)

Use Latent heat because ice transformed phase to water

Qice = (mass of ice)(heat fusion of water)

mass of silver * Csilver * (0-75) + mass of ice * heat fusion of water

Isolate and you'll get:

mass of ice * heat fusion of water = Csilver * mass of silver * 75

mass of ice = (Csilver * mass of silver * 75)/heat fusion of water