a piece of metallic iron (10 moles) was dissolved in concentrated hydrochloric acid. the reaction formed iron (II) chloride and hydrogen gas. how many moles of iron (II) chloride were formed?

Answer 1

Fe + 2HCl ==> FeCl2 + H2
1 mol Fe = 1 mol FeCl2; therefore,
10 mol Fe = 10 mols FeCl2.

Answer 2

a piece of metallic iron (moles) was dissolved in concentrated HCL.The reaction form H2 and FeCI2 write and balance the equation for this reaction and determine the amount of formed FeCL2 and the amount of used HCI