q = mass metal x specific heat metal x delta T.
q = 21.3 J.
Substitute and solve for specific heat.
A piece of metal with a mass of 5.50 grams changed in temperature from 25.0 to 55.0C when 21.3 joules was absorbed. The specific heat of the metal is
a. 0.256
b. 0.129
c. 3.91
d. 7.75
e. 0.710J g-1 oC-1
desperately need help!
3 answers
is it b?
yes