I assume we are to ignore the calorimeter constant.
[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass H2O x secific heat H2O x (Tfinal-Tinitial)] = 0.
Substitute and solve for s.h. metal.
A piece of metal weighing 5.10g at a temperature of 48.6 degree Celsius was placed in a calorimeter in 20.00 mL of water at 22.1 degree Celsius. The final equilibrium temperature was found to be 29.2 degree celsius. What is the specific heat of the metal?
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