[mass metal x specific heat metal x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
You have all except specific heat metal. Solve for that.
A piece of metal of mass 20.0g @ 100°C is placed in a calorimeter containing 50.7g of water at 22.0°C. The final temperature of the mixture is 25.7°C. What is the specific heat capacity of the metal? Assume that no energy leaves to the surroundings.
Not sure how to work this problem out. Help please? Thank u!
2 answers
If 46.1 g Cu at 11.6 C is placed in 85.0 g H2O at 72.4 C, what is the final temperature of the mixture? (specific heat capacities: Cu: 0.385 J/gK Water: 4.184 J/gK)?