A piece of iron Wales 0.52n in air,0.32n in water and 0.36n when immersed in carosen, what is the density of the liquid

Answer 1

To find the density of the liquid, we can use the principle of buoyancy. The buoyant force acting on the iron in the liquid can be calculated using the difference in weight between the iron in air and the iron in the liquid.

Let's denote the density of the liquid as ρ, the volume of the iron as V, the acceleration due to gravity as g, and the weight of the iron in air as W1.

Given:
Weight of iron in air, W1 = 0.52N
Weight of iron in water, W2 = 0.32N
Weight of iron in carosen, W3 = 0.36N

From the principle of buoyancy, we have:
W1 - W3 = ρVg

Substitute the given values:
0.52 - 0.36 = ρVg
0.16 = ρVg

The weight of the iron in air can be expressed as:
W1 = mg = ρironVg
Where ρiron is the density of iron and V is the volume of iron.

From the given values, we know that the density of iron is 7860 kg/m^3 and the volume of the iron can be calculated as follows:
V = W1 / (ρiron * g) = 0.52 / (7860 * 9.81)

Now, substitute the value of V into the equation W1 - W3 = ρVg:
0.16 = ρ * (0.52 / (7860 * 9.81)) * 9.81

Solving for ρ, we get:
ρ = 0.36 / (0.52 / 7860)

Therefore, the density of the liquid (carosen) is approximately 640 kg/m^3.