K.E. = (3/2)*k*T, where k is the Boltzman constant.
You must always take temperature in Kelvin, so the given temperature is 273K
=> (K.E.1) = (3/2)*k(273)
=> (K.E.2) = 2(K.E.1) = 2*(3/2)*k*(273)
= (3/2)*k*(2*273)
= (3/2)*k*(546)
The new temperature is double the old, since temperature and K.E. are directly proportional. The required temp. is 546K, or 273 degrees Celsius.
A piece of iron has a temperature of 0 zero degrees Celsius. At what temperature would the iron atoms have twice as much kinetic energy?
1 answer