A piece of gum comes lose from underneath an elevator that is moving upward at a speed of 6.30 m/s. The gum reaches the bottom of the elevator shaft in 3.00 s. With what speed does the gum hit the bottom of the shaft?

Question

A piece of gum comes lose from underneath an elevator that is moving upward at a speed of 6.30 m/s.  The gum reaches the bottom of the elevator shaft in 3.00 s.  With what speed does the gum hit the bottom of the shaft?

Henry · Answer

V = Vo + g*t. Vo = - 6.3 m/s. g = +9.8 m/s. t = 3 s. V = ?