Asked by Hammed barakat

A piece of copper ball of mass 20g at200 Is placed in a copper calorimeter of mass 60g containing 50g of water at 30 ignoring the heat loss calculate the final temperaure of the mixture
Answered by Anonymous
T is between 200 deg and 30 deg
heat out of copper = Cc * 20 ( 200-T)
heat into water = Cw * 50 (T-30)
they are equal
Answered by Elizabeth
Good question
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