q = mass x specific heat x delta T
593 = 77 x specific heat x (60-34)
Solve for specific heat
Part 2 uses the same formula along with the specific heat just calculated in part 1.
Post your work if you get stuck.
A piece of copper alloy with a mass of 77.0 g is
heated from 34.0◦C to 50.0◦C. In the process,
it absorbs 593 J of energy as heat. What is
the specific heat of this copper alloy?
Answer in units of J/g · K.
How much energy will the same sample lose if
it is cooled from 50.0◦
to 21.0◦C ?
Answer in units of J.
1 answer
1 answer