A physics book slides off a horizontal tabletop with a speed of 1.10m/s{\rm m}/{\rm s} . It strikes the floor in 0.350s{\rm s} . Ignore air resistance.

Answer 1

Assuming question wants height of table, Δy.

Use kinematics equation:
Δy = viyΔt + (1/2)gΔt²

Assuming 1.1m/s is horizontal velocity (slides off table), so viy=0
g=-9.8 m/s²

Δy=0+(1/2)(-9.8)(0.35²)
=-4.9(0.35²)
=-0.060 m
Floor is 0.06 m below table (not quite a table, usually 0.75 m high)

Horizontal distance covered:
vix*Δt
=1.1*0.35
=0.385 m.