Assuming question wants height of table, Δy.
Use kinematics equation:
Δy = viyΔt + (1/2)gΔt²
Assuming 1.1m/s is horizontal velocity (slides off table), so viy=0
g=-9.8 m/s²
Δy=0+(1/2)(-9.8)(0.35²)
=-4.9(0.35²)
=-0.060 m
Floor is 0.06 m below table (not quite a table, usually 0.75 m high)
Horizontal distance covered:
vix*Δt
=1.1*0.35
=0.385 m.
A physics book slides off a horizontal tabletop with a speed of 1.10m/s{\rm m}/{\rm s} . It strikes the floor in 0.350s{\rm s} . Ignore air resistance.
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