a) Trick question - it does not change. u = 1.90
b) v = -9.81 t
so |v| = 9.81 (0.410)
c) speed = sqrt (u^2+v^2)
d) tan (angle down from horizontal) = |v|/u
A physics book slides off a horizontal table top with a speed of 1.90 m/s. It strikes the floor after a time of 0.410 s. Ignore air resistance.
a) Find the magnitude of the horizontal component of the book's velocity just before the book reaches the floor.
b) Find the magnitude of the vertical component of the book's velocity just before the book reaches the floor.
c) Find the magnitude of the book's velocity just before the book reaches the floor.
d) Find the direction of the book's velocity just before the book reaches the floor.
PLEASE HELP ASAP. I HAVE AN ASSIGNMENT DUE TODAY ON THIS.
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