Asked by cristie

A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of . Determine the frequency (in hz) of the interacting photon.
Answered by bobpursley
frequency*wavelength=speed of light
Answered by Ling
First find: E = P^2/2Me + E(first ionization)

P= h / BroglieWavelength

E(first ionization)=21.7*10^-19

Me= 9.1*10^-31

h= 6.626*10^-34

Once E is found the find frequency:

frequency(hz)= E / h
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