A photograph has a length that is 6 inches longer than its width, x. So its area is given by the expression x(x+6) square inches. If the area of the photograph is 112 square inches, what is the width of the photograph?

The width of the photograph is blank inches.

The solution is

1 answer

To find the width of the photograph, we can set up the equation:

x(x + 6) = 112

Expanding the left side of the equation, we get:

x^2 + 6x = 112

Rearranging this equation into standard form, we get:

x^2 + 6x - 112 = 0

Now we can factor this quadratic equation:

(x + 14)(x - 8) = 0

Setting each factor to zero, we find two possible values for x:

x + 14 = 0
x = -14 (This is not a valid solution for the width of a photograph)

x - 8 = 0
x = 8

Therefore, the width of the photograph is 8 inches.