To find the width of the photograph, we can set up the equation:
x(x + 6) = 112
Expanding the left side of the equation, we get:
x^2 + 6x = 112
Rearranging this equation into standard form, we get:
x^2 + 6x - 112 = 0
Now we can factor this quadratic equation:
(x + 14)(x - 8) = 0
Setting each factor to zero, we find two possible values for x:
x + 14 = 0
x = -14 (This is not a valid solution for the width of a photograph)
x - 8 = 0
x = 8
Therefore, the width of the photograph is 8 inches.
A photograph has a length that is 6 inches longer than its width, x. So its area is given by the expression x(x+6) square inches. If the area of the photograph is 112 square inches, what is the width of the photograph?
The width of the photograph is blank inches.
The solution is
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