We can use the formula for the confidence interval for a population proportion:
CI = p̂ ± z*√(p̂(1-p̂)/n)
where:
p̂ = sample proportion = 0.46
z = z-score for 95% confidence level = 1.96
n = sample size = 100
Plugging in the values, we get:
CI = 0.46 ± 1.96*√(0.46(1-0.46)/100)
CI = 0.46 ± 0.098
CI = (0.362, 0.558)
Therefore, we can be 95% confident that the proportion of U.S adults who would not know their blood pressure or cholesterol levels if surveyed in a census is between 0.362 and 0.558.
A pharmaceuitical company found that 46% of 100 U,S adults sampled surveyed know neither their blood pressure nor their chlosterol levels assuming the person surveyed to be a simple random sample of u,s adults construct a 95% confidence interval for population proportion of u,s adults who would have given the same answer if a cenus had been taken instead of survey?
1 answer
1 answer