\(P(\text{Rebecka selects a poodle}) = \frac{2}{10} = \frac{1}{5}\)
After Rebecka selects a puppy, there are now 3 poodles out of 10 puppies in the store.
\(P(\text{Aaron selects a poodle}) = \frac{3}{10}\)
Therefore, the probability that they both select a poodle is:
\(P(\text{Rebecka selects a poodle}) \times P(\text{Aaron selects a poodle}) = \frac{1}{5} \times \frac{3}{10} = \frac{3}{50}\)
A pet store has 10 puppies, including 2 poodles, 4 terriers, and 4 retrievers. If Rebecka selects one puppy at random, the pet store replaces the puppy with a puppy of the same breed, then Aaron chooses a puppy at random. Find the probability that they both select a poodle.
The probability is
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